Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
Answer:
it is correct you are right
Answer:
the first equation
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let
h(t) ---> the height of an object in meters
t ----> the time in seconds
we have
For t=6 sec
substitute in the quadratic equation the value of t and solve for h
Answer: <B is congruent to <E
Step-by-step explanation:
There is no “angle,angle,angle” theorem when proving triangles are congruent.
There are 5 however that do:
ASA (angle, included side, angle)
SSS (side, side, side)
SAS (side, included angle, side)
AAS (angle,angle, non included side)
HL (hypotenuse,leg)
