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iris [78.8K]
3 years ago
12

2/3[8(5-2)^{2}+3*2] How do I distribute the 2/3 and then solve the rest?

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0
Before I distribute, I solve the inside first:

2/3[8(3)^2+6]

2/3[8(9)+6]

2/3[72+6]

2/3[78]

2*26= 52 is the answer

another way:

2/3[8(3)^2+6]

2/3[8(9)+6]

2/3[72+6]

(2/3)*72+(2/3)*6

2*24+2*2
48+4= 52
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<em><u>Given function is:</u></em>

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There are 12 months in a year

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f(3) = 2(3) - 1 = 6 - 1 = 5

f(4) = 2(4) - 1 = 8 - 1 = 7

f(5) = 2(5) - 1 = 10 - 1 = 9

f(6) = 2(6) - 1 = 12 - 1 = 11

f(7) = 2(7) - 1 = 14 - 1 = 13

f(8) = 2(8) - 1 = 16 - 1 = 15

f(9) = 2(9) - 1 = 18 - 1 = 17

f(10) = 2(10) - 1 = 20 - 1 = 19

f(11) = 2(11) - 1 = 22 - 1 = 21

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Total orders = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

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