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love history [14]
3 years ago
10

Last year’s match at Wimbledon between John Isner and Nicolas Mahut, which lasted 11 hours and 5 minutes, set a record for the l

ongest match in tennis history. The fifth set of the match lasted 8 hours and 11 minutes. Approximately what fraction of the whole match was taken up by the fifth set?
Mathematics
2 answers:
andre [41]3 years ago
8 0

Answer:

.738 as a fraction equals 738/1000

Step-by-step explanation:

Convert all to minutes.

11 hr 5min is 665 min.

8 hr 11min is 491.

Divide 491÷665

Answer .738

To write .738 as a fraction you have to write .738 as the numerator and put 1 as the denominator. Now you multiply the numerator and denominator by 10 as long as you get in numerator the whole number.

.738 = .738/1 = 7.38/10 = 73.8/100 = 738/1000

And finally,we have:

.738 as a fraction equals 738/1000

Oxana [17]3 years ago
6 0

Answer:

73.8%

Step-by-step explanation:

Convert all to minutes.

11 hr 5min is 665 min.

8 hr 11min is 491.

Divide 491÷665

Answer .738

Convert to fraction

Hope this helps

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yulyashka [42]

Answer:

  2√11

Step-by-step explanation:

The square of the hypotenuse (h) of the smaller triangle is given by the Pythagorean theorem:

  h² = 6² +8² = 100

The length of x is given by that same theorem:

  h² +x² = 12²

  x² = 12² -h² = 144 -100 = 44 . . . . . subtract h², fill in its value

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  x = 2√11 . . . . . . . simplify the root

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17x2 - 5x + 10x - 8x2
USPshnik [31]

Answer:

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Step-by-step explanation:

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AleksandrR [38]

Solution of the equation: x=6\frac{1}{2}

Step-by-step explanation:

The equation that we have to solve in this problem is:

13\frac{3}{4}+x=7\frac{1}{4}

The first step to do is to rewrite the mixed fractions as improper fractions. We have:

13\frac{3}{4}=\frac{13\cdot 4+3}{4}=\frac{52+3}{4}=\frac{55}{4}

And

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So the equation becomes

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Now we multiply by 4 each term on both sides, and we get

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Now we subtract 29 from both sides,

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Learn more about equations:

brainly.com/question/11306893

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No solution exists!

Step-by-step explanation:

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