Answer: Kara should have written the proportion in step 1 as;
Start Fraction 12 Over 72 End Fraction = Start Fraction 14 Over x End Fraction (that is 12/72 = 14/x)
Step-by-step explanation: The two similar triangles are given with the following dimensions;
Triangle VXW with side VW = 12 and side VX = 14. Also Triangle ZXY with side YZ = 72 and side XZ = x.
For two triangles to be similar, then there must be a similarity ration that is consistent with all sides in both triangles. This means if in the first triangle a side measures 1 unit and the similar side in the other triangle measures 5 units, then the ratio of similarity of corresponding sides shall be ratio 1 : 5. So for every corresponding side in the second triangle the measurement shall be times five of the side that corresponds in the first triangle.
Therefore, in triangle VXW and triangle ZXY, the corresponding sides are as follows;
VX = ZX
VW = ZY
XW = XY
What Kara did was as follows;
VX/ZY = VW/ZX
Which translates to 14/72 = 12/x
This was a wrong calculation because the side that corresponds to VX is ZX and not ZY.
The correct step should therefore have been;
VW/ZY = VX/ZX
12/72 = 14/x (Step 1)
12x = (72) (14) {Step 2}
x = 1008/12 (Step 3)
x = 84 (Step 4)
Given:
The inequality is:

To find:
The solution of the given inequality.
Solution:
We have,

Multiply both sides by 3.

Divide both sides by -8 and change the sign of inequality.


It can be written as:

Therefore, the correct option is A.
I need the picture. Or i can't see the pic
Identify the slope, m. This can be done by calculating the slope between two known points of the line using the slope formula.
Find the y-intercept. This can be done by substituting the slope and the coordinates of a point (x, y) on the line in the slope-intercept formula and then solve for b.
Answer:
perimeter of the shaded region = 88 +44+28 =160 cm
Step-by-step explanation:
perimeter of shaded region = length AO + arc OB + arc AB
length AO = radius of bigger circle
radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm
therefore AO = 28 cm
length of arc oB= half of circumference of smaller circle =
×14 = 44 cm
length of arc ab = half of circumference of bigger circle =
×28 =
×28= 88
therefore perimeter of the shaded region = 88 +44+28 =160 cm
area of the shaded region = half of area of bigger circle - half of area of smaller circle
=
=
solving we gen area of shaded region = 924