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BaLLatris [955]
3 years ago
10

X +3<4 -7 WHATS THE ANSWER PPL

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

x

12

Step-by-step explanation:

hope it helps

elena-14-01-66 [18.8K]3 years ago
6 0
The answer would b 12 ;)
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Name the quadrant or axis where the point (4.-6) is located.​
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Answer:

Step-by-step explanation:

(4, -6) is in quadrant IV , (quadrant 4)

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Gina visited the aquarium with some of her cousins, aunts and uncles. the group bought 18 admission tickets for $300 .Adult tick
Vitek1552 [10]

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well if their all adults it would be fifteen tickets if its multiple choice what r the choices?

Step-by-step explanation:

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What is (4x + 2) - (2x + 1)?
daser333 [38]
2x + 1

You can find that by switching the signs in the second set of parenthesis and then adding. 
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Find the derivative of f(x)= e^(4x) + e^-(4x)
ololo11 [35]

Answer:

f'(x)=4e^{4x} -4e^{-4x}

Step-by-step explanation:

To find this derivative, we will need to use the chain rule.

As there is a variable in the exponent we can use this formula:

f'(x)=u'e^u

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This gives us f'(x)=4e^{4x} -4e^{-4x}

4 0
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Read 2 more answers
The number of women graduating from​ 4-yr colleges in a particular country grew from 1930​, when 48,833 women earned a​ bachelor
Oxana [17]

Answer:

A(t) = 48833e^{0.0389t}

The exponential growth rate is r = 0.0389

Step-by-step explanation:

An exponential function for the number of women graduating from​ 4-yr colleges in t years after 1930 can be given by the following equation:

A(t) = A(0)e^{rt}

In which A(0) is the initial amount, and r is the exponential growth rate, as a decimal.

1930​, when 48,833 women earned a​ bachelor's degree

This means that A(0) = 48833

2004​, when approximately 870,000

2004 is 74 years after 1930, which means that A(74) = 870000

Applying to the equation:

A(t) = A(0)e^{rt}

870000 = 48833e^{74r}

e^{74r} = \frac{870000}{48833}

\ln{e^{74r}} = \ln{\frac{870000}{48833}}

74r = \ln{\frac{870000}{48833}}

r = \frac{\ln{\frac{870000}{48833}}}{74}

r = 0.0389

So

A(t) = A(0)e^{rt}

A(t) = 48833e^{0.0389t}

4 0
3 years ago
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