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Natasha_Volkova [10]
3 years ago
5

Find (g*f)(3) f(x)=|x+2| g(x)=-x² A -25 B 1 C 4 D -15

Mathematics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

Step-by-step explanation:

(gof)(3)  = g(f(3) )

but : f(3) = |3+2| =  5

(gof)(3)  = g(f(3) ) = g(5) = -(5)² = -25...answer ; A) -25

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Answer:

The answer is A

Step-by-step explanation:

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In △ABC, a=31, b=22, and c=18. Identify m∠A rounded to the nearest degree. HELP ME PLEASE!!
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Answer:

The measure of angle A is 101\°

Step-by-step explanation:

we know that

Applying the law of cosines

a^{2} =b^{2}+c^{2}-2(b)(c)cos(A)

substitute the values and solve for cos(A)

31^{2} =22^{2}+18^{2}-2(22)(18)cos(A)

cos(A)=[22^{2}+18^{2}-31^{2}]/(2(22)(18))\\ \\cos(A)=-0.193182\\ \\A=arccos(-0.193182)=101\°

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X=2 shown in the work below.

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Which expression is equivalent to 9q2-(3q - 7) +5q??<br> ) ?<br> 3
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9q^2-(3q - 7) +5q= \\\\=9q^2-3q + 7 +5q= \\\\=9q^2+2q + 7

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3 years ago
A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 98% conf
adelina 88 [10]

Answer:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.1 represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.07 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.01;0;1)", and we got z_{\alpha/2}=2.326, replacing into formula (b) we got:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

3 0
3 years ago
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