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Nadya [2.5K]
2 years ago
11

Find the derivative of f(x)= e^(4x) + e^-(4x)

Mathematics
2 answers:
ololo11 [35]2 years ago
4 0

Answer:

f'(x)=4e^{4x} -4e^{-4x}

Step-by-step explanation:

To find this derivative, we will need to use the chain rule.

As there is a variable in the exponent we can use this formula:

f'(x)=u'e^u

In this case, u=4x and u=-4x

This means that u'=4 and u'=-4 respectively

This gives us f'(x)=4e^{4x} -4e^{-4x}

xeze [42]2 years ago
4 0

Answer:

Step-by-step explanation:

note : (e^(u(x))' = (u(x))'e^(u(x)

f(x)= e^(4x) + e^-(4x)

f'(x) =4e^(4x) - 4 e^-(4x)

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Answer:

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6 0
3 years ago
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i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

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where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

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=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
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Answer:

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