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Vladimir79 [104]
3 years ago
11

Which set of ordered pairs represents a function?

Mathematics
1 answer:
alekssr [168]3 years ago
6 0

Answer: {(-6, -6), (-2,-2), (7,-6),(-5,0)}

Step-by-step explanation:

To find the ordered pairs that represent a function, we want to find one that doesn't have multiple outputs for one input.

{(-6, -6), (-2,-2), (7,-6),(-5,0)} is the correct answer because all the x are different, and have only one output.

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Identify the end behavior of the function f(x) = 6x^4 - 12x^3 +8x -10
goldfiish [28.3K]

Answer:

Step-by-step explanation:

This is a quartic  equation with a positive coefficient for x^4 so it is shaped like an M xo ir rises to both the left and the right.

4 0
3 years ago
Explain why 1/2 is not equivalent to 2/5.
juin [17]
Find ing the common denominator would make it 10.
for 1/2 to get to 10 you have to multiply by 5
1/2x5= 5/10
then you have to convert 2/5 to get the denominator to be 10
so you multiply 2/5 by 2
2/5x2= 4/10
5/10 is greater than 4/10
7 0
3 years ago
Read 2 more answers
Solve for V please!!!!!!!
enyata [817]

Answer:

v = 126°

Step-by-step explanation:

Since 54° and u are corresponding angles in parallel lines, they are equal, hence, u = 54°. u and v are Same Side Interior angles. In parallel lines, Same Side Interior angles are supplementary (meaning that they add up to 180°), therefore, v = 180 - u = 180 - 54 = 126°.

6 0
3 years ago
VODU
garri49 [273]

Answer:

r = ∛(3V/4π)

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr³.

We want to solve this first for r³ and then for r.

Multiplying both sides of V = (4/3)πr³ by 3 yields an equation without fractions:  3V = 4πr³.

Dividing both sides of this equation by 4π isolates r³:

       3V

r³ = -------

       4π

To find r, take the cube root of both sides of

       3V

r³ = -------

       4π

obtaining r = ∛(3V/4π)

3 0
3 years ago
Read 2 more answers
Need help !!!Divide 5a^2 + 6a - 9 into 25a^4 + 19a^2 - a - 78.
lana [24]
Hello,

Maybe i have not understood "into".

\dfrac{25a^4+19a^2-a-78}{5a^2+6a-9} =5a^2-6a+20+ \dfrac{-175a+102}{5a^2+6a-9}
6 0
3 years ago
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