Let c represent the weight of cashews and p the weight of pecans.
Then c + 10 = total weight of the nut mixture.
An equation for the value of the mixture follows:
$1.50(10 lb) + $0.75c = (c+10)($1.00)
Solve this equation for c: 15 + .75c = c + 10. Subtract .75c from both sides:
15 = 1c - 0.75c + 10. Then 5=0.25c, and c = 5/0.25, or 20.
Need 20 lb of cashews.
Check: the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15. The total value of the cashews is (20 lb)($0.75/lb), or $15. Does (20 lb + 10 lb)($1/lb) = $15 + $15? Yes. So c= 20 lb is correct.
Answer:
Step-by-step explanation:
u/4 + 9.9 = 16.9
Putting value of u = 24 in the equation
24/4 + 9.9 = 16.9
6 + 9.9 = 16.9
15.9 = 16.9
Bringing like terms on one
16.9 - 15.9 = 1
Answer:
See below
Step-by-step explanation:
We want to prove that
Taking the RHS, note
Remember that
Therefore,
Once
Then,
Hence, it is proved
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
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