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Bad White [126]
3 years ago
10

What type of symmetry does this figure have? Please help me I need to turn this in.

Mathematics
2 answers:
maria [59]3 years ago
7 0
A parallelogram has no reflectional symmetry! it's only rotational
Lelu [443]3 years ago
4 0
Both rotational symmetry and reflectional symmetry
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Solve for x pls. help
marta [7]

Answer:

the answer is 82

Step-by-step explanation:

here,

x°+57°+41°=180° ( sum of interior angle of a triangle)

or, x°+ 98°= 180°

or, x°=180°-98°

or, X°=82.

can u give me brailest

6 0
3 years ago
MO bisects angle LMN, angel LMO = 6x-20.angle NMO= 2x+32 find angle LMN?
ICE Princess25 [194]
If MO bisects angle LMN:
6 x - 20 = 2 x + 36
6 x - 2 x = 36 + 20
4 x = 56
x = 56 : 4
x = 14
∠ LMN = 2 · ( 2 · 14 + 36 ) = 2 · ( 28 + 36 ) = 2 · 64 = 128
Answer : C )  x = 14, ∠ LMN = 128
7 0
3 years ago
The 24 students in ms. lees class each collected an average of 18 cans for recycling. then 21 students in mr. galvez's class eac
belka [17]

This can be solve by using the average cans of each student collected and muliply it by the total students. Since for ms. Lee has 24 students and each student collected 18 cans on average, so the total can her class collected on average is 432 cans. For mr galveshas 21 students and collected 25 can per syudents on average, so the total is 525 cans. So 525 – 432 = 93 more cans the class of mr galvez collected

7 0
3 years ago
We're do I find a rate of change
SVEN [57.7K]
You can find the rate of change by taking it's derivative.
6 0
2 years ago
Read 2 more answers
How do you find the normal approximation without using the continuity correction?
Dennis_Churaev [7]
Let's say you want to compute the probability \mathbb P(a\le X\le b) where X converges in distribution to Y, and Y follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing Y such that its mean and variance are the same as those for X.

Example: If X is binomially distributed with n=100 and p=0.1, then X has mean np=10 and variance np(1-p)=9. So you can approximate a probability in terms of X with a probability in terms of Y:

\mathbb P(a\le X\le b)\approx\mathbb P(a\le Y\le b)=\mathbb P\left(\dfrac{a-10}3\le\dfrac{Y-10}3\le\dfrac{b-10}3\right)=\mathbb P(a^*\le Z\le b^*)

where Z follows the standard normal distribution.
8 0
3 years ago
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