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bagirrra123 [75]
2 years ago
5

For a certain experiment, the available experimental units are 12 people—six females (f) and six males (m). Use (1f, 2f, 3f, 4f,

5f, 6f) to denote the females and (1m, 2m, 3m, 4m, 5m, 6m) to denote the males. There are to be six treatment groups: A, B, C, D, E, and G. If a randomized block design is used, with the experimental units blocked by gender, which assignment of treatments is not correct? (5 points) A: (2f, 1m), B: (1f, 2m), C: (6f, 3m), D: (4f, 4m), E: (3f, 5m), G: (5f, 6m) A: (6f, 5m), B: (2f, 4m), C: (3f, 3m), D: (4f, 2m), E: (5f, 1m), G: (1f, 6m) A: (1f, 1m), B: (2f, 2m), C: (3f, 3m), D: (4f, 4m), E: (5f, 5m), G: (6f, 6m) A: (1f, 2f), B: (1m, 2m), C: (3f, 3m), D: (4f, 4m), E: (5f, 5m), G: (6f, 6m)
Mathematics
1 answer:
Kryger [21]2 years ago
6 0

Answer:

I believe the correct answer would be the last one.

Step-by-step explanation:

The units are supposed to be blocked by gender. However, the first two units in the final option are blocked with two females in one group, and two males in the next. This is inconsistent with the blocking method used for the rest of the units.

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Answer:

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Step-by-step explanation:

<u><em>Verify each option</em></u>

Part 1) The product of 8x(5x−6) is 40x^2−48x

we have

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Applying distributive property

x(5x)-x(6)-3(5x)+3(6)\\5x^2-6x-15x+18\\5x^2-21x+18

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