Solve the following equation for x. 5/4 x = 5 1/2

THERE IS A PICTURE! I KNOW YOU CAN SEE IT.....

alex41 [277]

The answer is 24 square units

4 0

3 years ago

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Can someone please help me? I'll gladly mark the best answer brainliest, and give 100 points!! Please and thank you :D

Alchen [17]

Answer:

Part A: The scale factor of the dilation that transforms triangle PQR to triangle P'Q'R' is 1/3. This is because triangle P'Q'R is smaller than PQR by 1/3

Part B: The coordinates after P"Q"R" are P"(1, -2) Q"(0, -3) R"(-1, 0)

Part C: No the triangles are not congruent because they are not the same size. If there wouldn't have been a dilation or reflection then it would've been congruent.

Step-by-step explanation:

I did this Exam already and got a 100% good luck.

3 0

3 years ago

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Equation of a line with a slope of -3 that passes through point (6,9)?

Serjik [45]

Answer:

Point-slope form: y-9 = -3(x - 6)

Standard form: y = -3x+27

Step-by-step explanation:

The point-slope form equation is y - y1 = m(x - x1). Because we are trying to find the equation that passes through (6,9), use these values as x1 and y1. In this equation m is the slope and we are also given that the slope is -3. This means that the equation in point-slope form is y-9 = -3(x - 6).

If it is asked for the equation in standard form, some simple moving of terms can accomplish that. Multiply out the -3 and get y-9 = -3x + 18. Add 9 to both sides to get a final answer of y = -3x+27.

7 0

4 years ago

SOLVE USING THE QUADRATIC FORMULA 1) y=3x^2-x-6 2) y=-5x^2+7x+3

kondor19780726 [428]

1) $x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}$

2) $x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}$

Step-by-step explanation:

Solving the equations using quadratic formula.

1) $y=3x^2-x-6$

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a =3, b = -1 and c= -6

Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-1)\pm\sqrt{(-1)^2-4(3)(-6)}}{2(3)}\\x=\frac{1\pm\sqrt{1+72}}{6}\\x=\frac{1\pm\sqrt{73}}{6}\\so, x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}$

2) $y=-5x^2+7x+3$

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a =-5, b = 7 and c= 3

Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(7)\pm\sqrt{(7)^2-4(-5)(3)}}{2(-5)}\\x=\frac{-7\pm\sqrt{49+60}}{-10}\\x=\frac{-7\pm\sqrt{109}}{-10}\\So, x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}$

Keywords: Solving Using Quadratic Formula

Learn more about Solving Using Quadratic Formula at:

#learnwithBrainly

3 0

4 years ago

What is -6 + 6? I will give 100 points to whoever answers this.

spayn [35]

0 duh because -6 is 6 before zero so if u add 6 u get 0

4 0

3 years ago

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