Suppose the heights of the members of a population follow a normal distribution. If the mean height of the population is 68 inch
es and the standard deviation is 4 inches, 95% of the population will have a height within which of the following ranges?
2 answers:
Answer:
60 -76 is the range
Step-by-step explanation:
As the graph shows, if we are in 2 standard deviations of the mean, we are in (34.1 + 13.6) *2 = 47.7*2 = 95.4 %
Our mean is 68
2 standard deviations is 2 * 4 = 8
68-8 = 60
68 * 8 = 76
We need to be between 60 and 76 to have at 95% confidence interval
The empirical rule states that at 95% the measurements would be within 2 standard deviations of the mean.
You are given a mean of 68 inches and a standard deviation of 4.
2 times the standard deviation = 2 x 4 = 8
So 95% of the heights would be between 68-8 = 60 inches and 68+8 = 76 inches.
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Step-by-step explanation:
Answer:
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We know from table that x intercept (when y or t(x) is 0) is -3
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y = 4+ 4x
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Answer:
28
Step-by-step explanation:
a^2+b^2=c^2
a^2+96^2=100^2
a^2+9216=10000
a^2=784
a^2= √784
a=28
