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spayn [35]
3 years ago
12

Suppose the heights of the members of a population follow a normal distribution. If the mean height of the population is 68 inch

es and the standard deviation is 4 inches, 95% of the population will have a height within which of the following ranges?

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
5 0

Answer:

60 -76 is the range

Step-by-step explanation:

As the graph shows, if we are in 2 standard deviations of the mean, we are in (34.1 + 13.6) *2 = 47.7*2 = 95.4 %

Our mean is 68

2  standard deviations is 2 * 4 = 8

68-8 = 60

68 * 8 = 76

We need to be between 60 and 76 to have at 95% confidence interval


Irina18 [472]3 years ago
4 0

The empirical rule states that at 95% the measurements would be within 2 standard deviations of the mean.


You are given a mean of 68 inches and a standard deviation of 4.

2 times the standard deviation = 2 x 4 = 8

So 95% of the heights would be between 68-8 = 60 inches and 68+8 = 76 inches.

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Find the area in square inches of a rectangle with a length of 5 inches and a width of 3 5/6 inches
andrey2020 [161]

Answer:

19 1/6 in^2

Step-by-step explanation:

just do multiplication bruv

5 0
3 years ago
For the given equation, find the values of a, b, and c, determine the direction in which the parabola opens, and determine the y
mariarad [96]

Answer:

Table A

Step-by-step explanation:

y  = 3x^2 +2x -8

The quadratic is in the form

y = a x^2 +bx+c

a = 3  b = 2 c = -8

Since a > 0 it opens up

The y intercept is c so the y intercept is -8

7 0
3 years ago
Suppose Evan is trying to build a frame out of popsicle sticks x inches long. The frame will have length (2x – 3) and width of (
erik [133]

Answer:

The correct option is A)  3 square inches; 2x^2-7x+6.

Step-by-step explanation:

It is given that the length of the frame is (2x-3) and the width is (x-2)

The area of the rectangle is: A=l\times w

Where, A is the area l is the length and w is the width of the rectangle.

Put l=(2x-3) and w=(x-2) in the area of the rectangle.

A=(2x-3)(x-2)\\A=2x^2-4x-3x+6\\A=2x^2-7x+6

The area of the frame expressed as a polynomial is 2x^2-7x+6.

Now substitute x=3 in A=2x^2-7x+6.

A=2(3)^2-7(3)+6\\A=18-21+6\\A=3

The area of the frame is 3 square inches.

Hence, the correct option is A)  3 square inches; 2x^2-7x+6.

8 0
3 years ago
The value of 33+4⋅(52−42)
joja [24]

We will use order of operations (PEMDAS) to solve this.

1.) 33+4(52-42) This is our equation. So, first we are gonna subtract 42 from 52.

2.) 33+4(10) Now that we did that, we are gonna add 4 to 33.

3.) 37(10) Lastly we are gonna multiply 37 by 10.

The answer is gonna be 370. If this helped, maybe consider giving me brainliest :)

7 0
3 years ago
Read 2 more answers
John invested $17,500 that
babymother [125]

Answer:

<u>The future value of the investment after 10 years is $ 29,240.53</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Principal = $ 17,500

Interest rate = 5.2% = 0.052 compounded semiannually

Time = 10 years = 20 semesters

2. What is the future value of the investment after 10 years​?

Let's use the formula of the Future Value, to calculate it for this investment:

FV = P * (1 + r) ⁿ

Let's replace with the real values:

FV = 17,500 * (1 + 0.052/2)²⁰

FV = 17,500 * 1.670887521

<u>FV = 29,240.53</u>

6 0
3 years ago
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