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yarga [219]
3 years ago
13

Please help and show work!!! Find the line perpendicular to y=-1/4x+7 and goes through the point (1,1).

Mathematics
1 answer:
expeople1 [14]3 years ago
8 0
The answer to the question

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if jennifer walked 9 miles in 3 hours, how many miles will jennifer walk in 5 hours at the same constant speed ?
alexandr402 [8]

15. is your answer. have a good day

3 0
2 years ago
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A collection of stamps consists of 22¢ stamps and 40¢ stamps. The number of 22¢ stamps is three more than four times the number
Artemon [7]

Answer:

27

Step-by-step explanation:

Let :

Number of 40¢ = x

Number of 22¢ = 4x + 3

Total stamp value = $8.34 = (8.34 * 100) = 834¢

40¢x + 22¢(4x + 3) = 834¢

40x + 88x + 66 = 834

128x = 834 - 66

128x = 768

x = 768 / 128

x = 6

Number of 22¢ stamp:

4(6) + 3 = 24 + 3 = 27

7 0
3 years ago
29 — 6x=5(1 – 6x)<br> Please show me the steps
Lady bird [3.3K]

Answer:

x= -1

Step-by-step explanation:

<u><em>START</em></u> 29 - 6x = 5(1 - 6x)

1.  Distribute

29 - 6x = 5 - 30x

2. Isolate the variable

~ <u>2a</u>. Add 30x to both sides

29 - 6x + 30x = 5 - 30x + 30x

~ <u>2b</u>. Subtract 29 from both sides

29 - 29 - 6x + 30x = 5 - 29 - 30x + 30x

3. Simplify

24x = -24

4. Solve

x = -1

<em><u>END</u></em>

5 0
3 years ago
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 10 N acts on
Step2247 [10]

Answer:

The force is 12 N

Step-by-step explanation:

* Lets explain how to solve the problem

- Direct variation is a relationship between two variables that can

 be expressed by an equation in which one variable is equal to a

 constant times the other

- If y ∝ x , then y = kx , where k is the constant of variation

* Lets solve the problem

- The force acting on the object varies directly with the object's

  acceleration

∵ The force is F in newtons and a is the acceleration is m/s²

∴ F ∝ a

∴ F = ka

- To find k substitute F and a by the initial values of them

∵ A force of 10 N acts on a certain object, the acceleration of the

  object is 5 m/s²

∵ F = 10 N when a = 5 m/s²

∵ F = ka

∴ 10 = k(5)

- Divide both sides by 5

∴ K = 2

- Substitute the value of k in the equation

∴ F = 2a

- Lets find the force when the acceleration is 6 m/s²

∵ a = 6 m/s²

∴ F = 2(6) = 12

* The force is 12 N

5 0
2 years ago
State the domain &amp; range!
Simora [160]

Answer:

Domain=x:x is a natural number less than 6: x≠4

Range= x:x is a natural number, 3>=x<=1

8 0
2 years ago
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