Answer:
-(4,-3)
Step-by-step explanation:
You need to find the slope from point o to b, and then multiply it three times to get to b prime.
Answer:
5.50 years
Step-by-step explanation:
A = P
A = final amount
P = initial principal balance
r = interest rate
n = number of times interest applied per time period
t = number of time periods elapsed
3178 = 2000(1+.086/2)^2t
t = 5.499904413
Jason’s camp counselor job pays a higher hourly rate than Mia’s lifeguard job, $9.00 compared to $8.75
What is the hourly rate of Jason from the lifeguard job?
The hourly rate of the lifeguard job can determined as the total amount earned divided by the total of number of hours worked
hourly rate=($52.50+$70.00+$43.75)/(6+8+5)
hourly rate=$8.75
The lifeguard job when compared to the camp counselor for the summer job pays lesser hourly rate of $8.75 as against $9.00 per hour from latter job, hence, Jason’s camp counselor job pays a higher hourly rate than Mia’s lifeguard job.
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Answer:
h(x) = (x + 4)^2 - 2
Step-by-step explanation:
Start with the red graph: f(x) = x^2
First we move the entire graph 4 units to the left. The resultant function is g(x) = (x + 4)^2.
Next, we move this latest graph 2 units down. The resultant function (and answer to this question) is h(x) = (x + 4)^2 - 2
Step-by-step explanation:
H0: u = 150
H1: u ≠ 150
Total sum = 15933.24
N = 100
Mean = 15933.24/100
= 159.3324
σ² = 25954.03 - (159.3324)²/100
σ² = 556.213
σ = √556.213
σ = 23.8162
Testing hypothesis
t = (bar x - u)/ σ/√n
= 159.3324-150/23.8162/√100
= 3.91
We will have a p value of 0.02
0.0002 < 0.01
We reject null hypothesis at 1% level of significance
C. Mean = 159.3324
Se= 2.3936
Df = 100-1 = 99
Critical value at 0.01 = +-2.626
T = x-u/s.e
= -2.626 =( x -150)/2.3936
When we cross multiply and solve this
X = 143.714 for the lower tail
2.626 = (x-159)/2.3936
= 156.286 for upper tail.
We therefore reject H0 at
Bar X <= 143.71
Bar X >= 156.286
At 10%
Critical t = 1.660
-1.660 = (x - 150)/2.3936
Solving this ,
X =146.02 at the lower tail
1.660 = (x-150)/2.3936
X = 153.97
We reject H0 at
X<= 146.03
X>=153.97