Rewrite the parabola in standard form and use this formula to find the vertex (h,k).
= (2,-1)
= (2,-1)
What is the slope of the line 7, 0 and -5, 0
1 answer:
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= -
given
= 5 ( cross- multiply )
5(x + y) = x - y
5x + 5y = x - y ( subtract (x - y) from both sides )
4x + 6y = 0 ( subtract 6y from both sides )
4x = - 6y
= -
= -
circle: x2+ y2 = 2
parabola: y = 2x2 – 3
The standard form of equation of circle is:
( x – h )^2 + ( y – k )^2 = r^2
We are given the equation x^2 + y^2 = 2.
Where h and k are the x and y coordinates of the center.
Basing on the standard equation, the center is at (0 , 0) and r =
The standard form of equation of parabola with the axis of symmetry parallel to the y-axis is:
(x - h)^2 = 4p (y - k)
Rearranging the given equation into this form:
x^2 = (½) y + 3/2
x^2 = ½ (y + 3)
Since 4p is positive value, therefore the parabola is opening up. The vertex is located at (0 , -3).
<span>Answer: circle with its center at (0, 0) and a radius of </span>