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Andreyy89
3 years ago
8

What is the slope of the line 7, 0 and -5, 0

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

Slope =  (Y2 -Y1) ÷ (X2 -X1)

Slope = (0 -0) / (-5, -7)

Slope = 0 / -12 = 0

The slope of the line is zero.  It is perfectly horizontal.


Step-by-step explanation:


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What is the final amount if 975 is increased by 1% followed by a further 9% increase?
alexgriva [62]
975 x 1.01 = 984.75
984.75 x 1.09 = 1073.38
3 0
3 years ago
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
3 years ago
I’m boredddd
Roman55 [17]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Find sin theta if theta is an angle in standard position and the point with coordinates (3, -4) lies on the terminal side of an
alisha [4.7K]

Answer:

\sin \theta=-\frac{4}{5}

Step-by-step explanation:

Given:

Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).

So, the 'x' value is 3 and 'y' value id -4.

Using Pythagoras Theorem, we find the hypotenuse.

Hypotenuse = \sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

Now, using the sine ratio for the angle, we have

\sin \theta=\frac{Opposite}{Hypotenuse}\\\sin \theta=\frac{-4}{5}\\\sin \theta=-\frac{4}{5}

Therefore, the value of \sin \theta is -\frac{4}{5}.

The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,

4 0
3 years ago
7. A business begins with $1,000,000 from its owners. It places $100,000 into a bank account which it wishes to maintain as a ca
joja [24]

Answer:

The amount need to borrow a owner is $100,000

Step-by-step explanation:

The total amount a owner having to start a business = $1,000,000.

He wishes to place $ 100,000 into bank account to maintain as cash reserve.

Now the amount he left with to spent in business purposes = $1,000,000 - $100,000 = $ 900,000.

He needs to purchase equipment and material of $1,000,000

But he is left with only $900,000.

So the amount he has to borrow to fulfill his business requirement is

= $1,000,000 - $900,000 = $100,000

8 0
3 years ago
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