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Andreyy89
3 years ago
8

What is the slope of the line 7, 0 and -5, 0

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

Slope =  (Y2 -Y1) ÷ (X2 -X1)

Slope = (0 -0) / (-5, -7)

Slope = 0 / -12 = 0

The slope of the line is zero.  It is perfectly horizontal.


Step-by-step explanation:


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\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
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\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
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