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harkovskaia [24]
3 years ago
9

What are two decimals equivalent to 3.7

Mathematics
1 answer:
Travka [436]3 years ago
6 0
Hm i think 3.700 and 3.70
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After earning 300 points on a game show, Katie got to compete in the bonus round. By the end of the bonus round, she had a total
inessss [21]

Answer:

500

Step-by-step explanation:

First we make an equation to find the score for the bonus round. x is the score for the bonus round .

300 + x = 800

Next we subtract 300 from both sides of the equation

300 - 300 + x = 800 - 300

Which get us

0 + x = 500

x = 500

Her score in the bonus round is 500

4 0
4 years ago
please help me. Which one is it I think it's the first one because it's not random but they all seem pretty random
matrenka [14]
Im almost positive its the second one
8 0
3 years ago
What’s is sherry error?
beks73 [17]

Answer:

the answer is B.

Step-by-step explanation:

It makes the problem solve smoother.

3 0
3 years ago
What is the slope intercept form of y =8x + 4
Readme [11.4K]
Looks like it's already in slope-intercept form.
slope-intercept form: y = mx + b
in this case, m is 8 and b is 4
4 0
3 years ago
You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

    The angle of elevation  is  \theta_1  =  15 ^o =  \frac{\pi}{12}

     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

          tan \theta  =  \theta  + \frac{\theta ^3 }{3}

So given that \theta =  15 \ which \ is \ small

       h = D (\theta + \frac{\theta^3}{3} )

       dh = D (1 + \theta^2) d\theta

=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

Now from the question the relative error of height should be at  most

        \pm  p%

=>    \frac{dh}{h} =   \pm p

=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

 =>       d\theta_1  = 0.25 p

Converting to degree

           d\theta_1  = (0.25* 57.29) p

            d\theta_1  =(14.36p)^o

4 0
3 years ago
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