The RPM at which the engine is putting out Maximum power is 6875 RPM.
The maximum horsepower is; 1548.521 HP
<h3>How to find the maximum value of a function?</h3>
We are told that the engine in a car has a power curve approximated by;
y = -x²/30000 + 22x/48 - 27
where;
x is the RPM
y is the horsepower generated
A) The RPM that generates the most power would be the value of x at dy/dx = o
Thus;
dy/dx = -2x/30000 + 22/48
At dy/dx = 0;
-2x/30000 + 22/48 = 0
22/48 = 2x/30000
2x = (22 * 30000)/48
x = (22 * 30000)(2 * 48)
x = 6875 RPM
B) Maximum horsepower would be;
y(6875) = -(6875)²/30000 + 22(6875)/48 - 27
= 1548.521 HP
Read more about Maximum value of a function at; brainly.com/question/5722003
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Answer:
square
Step-by-step explanation:
when multiplied by itself the number is squared
The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1
Ivan
Answer:
0.6 probability that
Step-by-step explanation:
The probability distribution is given in the table.
Probability that x is between -2 and 2.
Between -2 and 2, inclusive, we have -2, 0 and 2. So
From the table:
. So
0.6 probability that
Answer:
the answer is 48:34
Step-by-step explanation:
82 - 48 = 32
so 48 : 32
Answer:
D. 5x^2 + 2y^2 + 12x + 5y
Step-by-step explanation:
6x + 2y + y^2 + 6x + 2y + y^2 + 4x^2 + x^2 + y
6x + 6x = 12x
12x + 2y + y^2 + 2y + y^2 + 4x^2 + x^2 + y
2y + 2y + y = 5y
12x + 5y + y^2 + y^2 + 4x^2 + x^2
y^2 + y^2 = 2y^2
2y^2 + 4x^2 + x^2 + 12x + 5y
4x^2 + x^2 = 5x^2
2y^2 + 5x^2 + 12x + 5y
5x^2 + 2y^2 + 12x + 5y