Write the first 4 terms of the arithmetic sequence With first term 37 and common difference 9
2 answers:
Answers:
first term = 37
second term = 46
third term = 55
fourth term = 64
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Explanation:
Start at 37. Add 9 to this term to get the second term. Add 9 to that result to get the next term, and so on.
first term = 37
second term = 37+9 = 46
third term = 46+9 = 55
fourth term = 55+9 = 64
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The nth term formula is
a(n) = 9n+28
It can be found by plugging a = 37 and d = 9 into the general form
a(n) = a + d*(n-1)
Answer:
First term: 37
2nd term: 46
3rd term: 55
4th term: 64
Step-by-step explanation:
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