Answer:
Point slope is ( Y+4) = 1/2(x+3)
Slope intercept is Y = 1/2(x) -5/2
Step-by-step explanation:
For the point slope form.
Given the point as (-3,-4)
And the gradient m = 1/2
Point slope form is
(Y - y1) = m(x-x1)
So
X1 = -3
Y1 = -4
(Y - y1) = m(x-x1)
(Y - (-4)) = 1/2(x -(-3))
( Y+4) = 1/2(x+3)
For the slopes intercept form
Y = mx + c
We can continue from where the point slope form stopped.
( Y+4) = 1/2(x+3)
2(y+4)= x+3
2y + 8 = x+3
2y = x+3-8
2y = x-5
Y = x/2 - 5/2
Y = 1/2(x) -5/2
Where -5/2 = c
1/2 = m
we know that
A half-acre is equal to----------> 
Let
x---------> the length side of the building lot
y--------> the width side of the building lot
A------> Area of the building lot
x=5y-------> equation 1


--------> equation 2
substitute equation 1 in equation 2
![2,023.43=[5y]*y](https://tex.z-dn.net/?f=2%2C023.43%3D%5B5y%5D%2Ay)

<u>Find the value of x</u>

therefore
<u>the answer is</u>
the dimensions of the building lot are 100.55 m* 20.11 m
Answer/Step-by-step explanation:
Question 1:
Interior angles of quadrilateral ABCD are given as: m<ABC = 4x, m<BCD = 3x, m<CDA = 2x, m<DAB = 3x.
Since sum of the interior angles = (n - 2)180, therefore:

n = 4, i.e. number of sides/interior angles.
Equation for finding x would be:



(dividing each side by 12)

Find the measures of the 4 interior angles by substituting the value of x = 30:
m<ABC = 4x
m<ABC = 4*30 = 120°
m<BCD = 3x
m<BCD = 3*30 = 90°
m<CDA = 2x
m<CDA = 2*30 = 60°
m<DAB = 3x
m<DAB = 3*30 = 90°
Question 2:
<CDA and <ADE are supplementary (angles on a straight line).
The sum of m<CDA and m<ADE equal 180°. To find m<ADE, subtract m<CDA from 180°.
m<ADE = 180° - m<CDA
m<ADE = 180° - 60° = 120°
Answer:
answer is 2.
Step-by-step explanation:
Answer:
YES
Step-by-step explanation:
As x increases by 3 each time, y also increases by a steady number each time, which is 6. This means that x and y are in a proportional relationship with a 1:2 ratio.