1/2y^2=1/2x^2+8. The curve's slope at (x,y) is x/y, so dy/dx=x/y. To solve this differential equation, rearrange it to: y*dy=x*dx, and by integrating both sides, we get 1/2y^2=1/2x^2+C (some constant). Plug in (0,4) into this equation, 8=0+C, so C=8. The curve's equation is 1/2y^2=1/2x^2+8.
Answer:
1. x² + 3x - 5 = 0
2. x² - x = 3 x + 7
4. 7x² + 14x = 0
Step-by-step explanation:
A Quadratic equation takes the form;
ax² + bx + c = 0
a, b, c are constants and a cannot be 0.
Options 1 fits this;
x² + 3x - 5 = 0
Option 2 fits this as well;
x² - x = 3 x + 7
x² -x - 3x - 7 = 0
x² - 4x - 7 = 0
Option 4 fits this as well if c = 0.
7x² + 14x + 0 = 0
Range=highest number-lowest number
15-5=10
Range=10
