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e-lub [12.9K]
2 years ago
6

Using the picture below, which angle is alternate exterior to angle 2?

Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0

Answer:

alternate exterior means outside of the two parallel lines so your answer is 7 because alternate means other side of transversal

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A school gives awards in five subjects to a class of 30 students but no one is allowed to win more than one award. how many outc
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6 cause u have to multiply 30 and 5
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3 years ago
(-5,-4) rotated 270° counterclockwise
stepladder [879]

Answer:

(4, - 5 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (- y, x ) , thus

(- 5, - 4 ) → (4, - 5 )

6 0
3 years ago
Which graph matches the exponential function f(x) = 2(1.5)x?
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The third one pls mark me brainliest
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3 years ago
Boeing currently produces five models of airplanes for commercial sale. The airline that Lauren works for is rapidly expanding a
Sedbober [7]

Answer:

The number of combinations will she have to analyze is  10.

Step-by-step explanation:

We know that Boeing currently produces five models of airplanes for commercial sale.  The airline that Lauren works for is rapidly expanding and would like to purchase three airplanes of different models to service various routes.  We calculate the number of combinations will she have to analyze.

C^5_3=\frac{5!}{3!(5-3)!}=\frac{5\cdot 4\cdot 3!}{3!\cdot 2\cdot 1}=10

The number of combinations will she have to analyze is  10.

4 0
3 years ago
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
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