I=prt. I=600(.07)(2). I=42(2). I=84. Juanita will pay $84 interest :)
Data set: <span>2, 10, 10, 11, 11, 12, 12, 12, 13, 14, 14
</span>
range: 14 - 2 = 12
median: 12
lower quartile = 10
interquartile range = 4
Data set w/o outlier 2: <span>10, 10, 11, 11, 12, 12, 12, 13, 14, 14
range: 14 - 10 = 4
median: 12
lower quartile: 10.5
interquartile range = 3.5
The value that change the most by removing the outlier is A.) THE RANGE.</span>
Answer:
the first one is the answer
The first one! you probably got confused from the top two, they have the same data but the first one would be correct because the number line is in the correct order
The line segment is 10 units long, the point that divides it can be 3 up or 7 up from B.
Therefore, the y-value can be -1 or 3.
