Step-by-step explanation:
arctan(x) is less than π/2 for x > 0. Therefore, if we say g(x) = 13 (π/2) / eˣ, then f(x) < g(x) for all values of x > 0.
g(x) = 13 (π/2) / eˣ
g(x) = 13π/2 · (1/e)ˣ
So g(x) is a geometric series where r = 1/e. Since |r| < 1, the series converges.
Since g(x) converges, the smaller f(x) also converges.
I think it would be 2,680%
If I’m wrong I owe u a donut
<em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>Indian </u></em><em><u>System</u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
(a) 23,45,678
(b) 56,78,090
<em><u>2</u></em><em><u>.</u></em> <em><u>International</u></em><em><u> </u></em><em><u>System</u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>
(a) 234,589
(b) 9,807,062
Answer:
this triangle seems to be an isosceles, obtuse triangle
