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Andrej [43]
4 years ago
14

Barbara buys a box of pens for $4. For every additional box she buys, she gets a $1 discount. Which expression represents the to

tal cost of the pens, c, as a function of the number of boxes, b? c = f(b) = 4b – 1 c = f(b) = 4b + 1 c = f(b) = 3b + 4 c = f(b) = 4b + 3 c = f(b) = 4 + 3(b – 1)
Mathematics
1 answer:
Andreyy894 years ago
7 0
$4 x c - 1
I don't know reallly
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The two conditional relative frequency tables show the results of a neighborhood survey on the number and types of gardens in th
umka2103 [35]

Answer:

...what :V

Step-by-step explanation:

4 0
3 years ago
What is the equation of the line that passes through the point(−7,−1) and has a slope of 1?
bonufazy [111]

Answer:

y=x+6

Step-by-step explanation:

Put (-7,-1) into

y-y1=m(x-x1) form, and m=1 (the slope)

y+1=1(x+7)

y+1=x+7

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Happy Holidays!

4 0
3 years ago
f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many
Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Assuming that the proportion is estimated \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{2.58})^2}=1849  

And rounded up we have that n=1849

7 0
3 years ago
Someone helped me please
suter [353]

Answer:

Step-by-step explanation:

add all student to get total.

30+28+14+28=100 total students

28+14+28=70 students that do not supprt ashley.

70/100 is the probability the student chosen at random will not support ashley.

.7 in simplified decimal format.

4 0
3 years ago
Solve for x and y 9/x-4/y=8
borishaifa [10]
You can solve <span>9/x-4/y=8 for x or for y but NOT at the same time.

Solving for x:  </span><span>9/x-4/y=8       Mult all 3 terms by xy to eliminate the fractions.

9(xy)/x - 4xy/y = 8xy         =>       9y - 4x = 8xy, or 9y = 4x + 8xy = 4x(1+2y)

                                                                        then 9y = x [ 4(1+2y) ]
                                                                                     9y
                                                            therefore x = ------------
                                                                                  4(1+2y)

Solve for y using a similar approach.

</span>
7 0
3 years ago
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