3 years ago

Help? i’ll give brainliest and points !

Mathematics

1 answer:

madam [21]3 years ago

5 0

(2,0) okeyyyyyyyyyy :)

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The given plane, $x-y+z=3$ , has normal vector $\vec n = \langle1,-1,1\rangle$ . Any plane parallel to this one has the same normal vector.

Let $(x,y,z)$ be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

$\langle x,y,z\rangle - \langle 1,1,-1\rangle = \langle x-1, y-1, z+1 \rangle$

and this is perpendicular to $\vec n$ .

So the equation of the plane is

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