The numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
Since a furniture company has 480 board ft of teak wood and can sustain up to 450 hours of labor each week, and each chair produced requires 8 ft of wood and 12 hours of labor, and each table requires 20 ft of wood and 15 hours of labor, to determine, if a chair yields a profit of $ 65 and a table yields a profit of $ 90, what are the numbers of chairs and tables that should be produced each week in order to maximize the company's profit, the following calculation should be done:
- 16 chairs; 24 tables
- Time used = 16 x 12 + 24 x 15 = 192 + 360 = 552
- Wood used = 16 x 8 + 24 x 20 = 128 + 480 = 608
- 15 chairs; 18 tables
- Time used = 15 x 12 + 18 x 15 = 180 + 270 = 450
- Wood used = 15 x 8 + 18 x 20 = 120 + 360 = 480
- 12 chairs; 28 tables
- Time used = 12 x 12 + 28 x 15 = 144 + 420 = 564
- Wood used = 12 x 8 + 28 x 20 = 96 + 540 = 636
- 18 chairs; 20 tables
- Time used = 18 x 12 + 20 x 15 = 216 + 300 = 516
- Wood used = 18 x 8 + 20 x 20 = 144 + 400 = 544
Therefore, the only option that meets the requirements of time and wood used is that of 15 chairs and 18 tables, whose economic benefit will be the following:
- 15 x 65 + 18 x 90 = X
- 975 + 1,620 = X
- 2,595 = X
Therefore, the numbers of chairs and tables that should be produced each week in order to maximize the company's profit is 15 chairs and 18 tables.
Learn more in brainly.com/question/14728529
Answer:
22.35 m/s
Step-by-step explanation:
The distance is always a positive unit, so distance traveled (d) = 15 miles
Time (t) = 0.3 hours
Time (t) = 0.3 * 60 = 18 minutes
(1 hour = 60 minutes)
Velocity (v) = ?
The formula of distance is: d = v*t
=> v = d/t = 15/18 = 0.83 miles/minute
we can also calculate velocity is meter/sec, for that
1 minute = 60 sec
=> 18 mins = 18*60 = 1080 sec
1 mile = 1609.34 meters
=> 15 miles = 15 * 1609.34 = 24,140 m
hence,
v = 24,140/1080 = 22.35 m/s
Answer:
true
Step-by-step explanation:
The answer is 5/3 can I have the some points
Answer:
see explanation
Step-by-step explanation:
I don't have graphing facilities but can give you the vertex and 1 other point.
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = - 
y = - x² - 2x + 8 ← is in standard form
with a = - 1 and b = - 2 , then
x = - 
= - 1
Substitute x = - 1 into the equation for corresponding value of y
y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9
vertex = (- 1, 9 )
To obtain another point substitute any value for x into the equation
x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph
x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0 then (2, 0 ) is a point on the graph
