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3 years ago

Help me almost done!

Mathematics

1 answer:

Andreyy893 years ago

6 0

Cos 60° is ½

and sin 60° is √3/2

so it is true....

that table may help you

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Can someone help me please <br> Brainiest answer to whoever is first

KiRa [710]

Answer:

Step-by-step explanation:

Surface area of small box = 2(4×10) + 2(4×14) + 2(10×14)

= 2(40+56+140)

= 472 cm²

Surface area of large box = 2(4×20) + 2(4×14) + 2(20×14)

= 2(80+56+280)

= 832 cm²

832 - 472 = 360 cm²

Answer: C

5 0

3 years ago

Line segment TU has endpoints (-7,10) and (-6,-5). What is the length of TU to the NEAREST TENTH?

Sindrei [870]

Answer: 15 units

Step-by-step explanation:

Given

The endpoints of the line segment are $(-7,10)\ \text{and}\ (-6,-5)$

The length of the line segment is given by the distance formula i.e.

$d=\sqrt{\left( x_2-x_1\right)^2+\left( y_2-y_1\right)^2}$

Insert the values,

$\Rightarrow d=\sqrt{\left( -6+7\right)^2+\left( -5-10\right)^2}\\\Rightarrow d=\sqrt{1^2+\left( -15\right)^2}\\\Rightarrow d=\sqrt{1+225}\\\Rightarrow d=15.0\ \text{units}$

Therefore, the length of line segment TU is 15 units

7 0

3 years ago

What is the diameter of a cylinder whose volume is 211.75 cm2and height is22 cm

uysha [10]

Step-by-step explanation:

please mark me as brainlest

6 0

3 years ago

Find the distance between two points ( -1,1) and (2,-4)

sladkih [1.3K]

Answer:

The distance between two points ( -1,1) and (2,-4) is:

$d=\sqrt{34}$ or d = 5.8 units.

Step-by-step explanation:

Given the points

(-1, 1)

(2, -4)

Finding the distance between (-1, 1) and (2, -4) using the formula

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

substitute (x₁, y₁) = (-1, 1) and (x₂, y₂) = (2, -4)

$=\sqrt{\left(2-\left(-1\right)\right)^2+\left(-4-1\right)^2}$

$=\sqrt{\left(2+1\right)^2+\left(-4-1\right)^2}$

$=\sqrt{3^2+5^2}$

$=\sqrt{9+25}$

$=\sqrt{34}$ units

$d = 5.8$ units

Therefore, the distance between two points ( -1,1) and (2,-4) is:

$d=\sqrt{34}$ or d = 5.8 units.

3 0

3 years ago

What is a buffer made from?

Leona [35]

Answer:

Step-by-step explanation:

A buffer must contain a weak acid and its conjugate base. There are several ways a solution containing these two components can be made: Buffers can be made from weak acids or base and their salts. ... Buffers can be made from two salts that provide a conjugate acid-base pair.

8 0

3 years ago

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