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padilas [110]
3 years ago
12

What is the product of 9/20 - 1/4

Mathematics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

\frac{1}{5}

Step-by-step explanation:

\frac{9}{20} - \frac{1}{4}

Make sure they have a common denominator. To do so, you must find a number the both have in come. Here, the number they have in common is 20.

What times 4 equals 20? 5. Whatever you do to the denominator you must do to the numerator.

\frac{5}{5} × \frac{1}{4} = \frac{5}{20}

Now you have \frac{9}{20} - \frac{5}{20} = \frac{4}{20}

Then you can simplify \frac{4}{20} to \frac{1}{5} by dividing it by \frac{4}{4}

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Use the given scale factor and the side lengths of the scale drawing to
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Answer:

A

Step-by-step explanation:

A scale drawing is a reduced  or enlarged form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced or enlarged at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

a = 12 inches / 6 = 2 inches

b = 9 inches / 6 = 1.5 inches

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What is the area of the triangle shown below?<br> m2
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{[5*12]/2}+{[12*25]/2]= 30+150=180m
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Which of the following is the equation that says that the product of a number and ten is equal to 20 percent of that number ?
Savatey [412]

Answer:

It is D.

Step-by-step explanation:

The produce of the number and 10 is 10n.

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4 years ago
Let c be the path c(t) = (2t, t2, log(t)), defined for t &gt; 0. find the arc length of c between the points (2, 1, 0) and (12,
V125BC [204]
The path starts at t=1 and ends at t=6, so we have an arc length of


\displaystyle\int_{\mathcal C}\mathrm dS=\int_{t=1}^{t=6}\|\mathbf c'(t)\|\,\mathrm dt
=\displaystyle\int_1^6\sqrt{2^2+(2t)^2+\left(\frac1t\right)^2}\,\mathrm dt
=\displaystyle\int_1^6\sqrt{4t^2+4+\frac1{t^2}}\,\mathrm dt
=\displaystyle\int_1^6\frac1t\sqrt{4t^4+4t^2+1}\,\mathrm dt
=\displaystyle\int_1^6\frac1t\sqrt{(2t^2+1)^2}\,\mathrm dt
=\displaystyle\int_1^6\frac{2t^2+1}t\,\mathrm dt
=\displaystyle\int_1^6\left(2t+\frac1t\right)\,\mathrm dt
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4 years ago
The graph of F(x), shown below in pink, has the same shape as the graph of
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<em>Greetings from Brasil...</em>

In this problem we have 2 translations: 4 units horizontal to the left and 3 units vertical to the bottom.

The translations are established as follows:

→ Horizontal

F(X + k) ⇒ k units to the left

F(X - k) ⇒ k units to the right

→ Vertical

F(X) + k ⇒ k units up

F(X) - k ⇒ k units down

In our problem, the function shifted 4 units horizontal to the left and 3 units vertical to the bottom.

F(X) = X³

4 units horizontal to the left: F(X + 4)

3 units vertical to the bottom: F(X + 4) - 3

So,

F(X) = X³

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