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Yakvenalex [24]
3 years ago
12

Consider the following expression -2m(m+n-4)+5(-2m+2n)+n(m+4n-5) which of the following is an equivalent expression

Mathematics
1 answer:
velikii [3]3 years ago
3 0
The answer is:

-2m²+4n²-mn-2m+5n

aka letter c in algebra nation
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Find the missing side of The Triangle ​
saul85 [17]

Step-by-step explanation:

By phythagorous theorem,

AC²=AB²+BC²

AC²=36+64

AC²=100

AC=root of 100

AC=10

7 0
3 years ago
(1+x^2)dy/dx+2xy-4x^2=0 bu using Bernoulli's Equation
erastovalidia [21]
Not of Bernoulli type, but still linear.

(1+x^2)\dfrac{\mathrm dy}{\mathrm dx}+2xy=4x^2

There's no need to find an integrating factor, since the left hand side already represents a derivative:

\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=(1+x^2)\dfrac{\mathrm dy}{\mathrm dx}+2xy

So, you have

\dfrac{\mathrm d}{\mathrm dx}[(1+x^2)y]=4x^2

and integrating both sides with respect to x yields

(1+x^2)y=\displaystyle\int4x^2\,\mathrm dx
(1+x^2)y=\dfrac43x^3+C
y=\dfrac{4x^3}{3(1+x^2)}+\dfrac C{1+x^2}
7 0
3 years ago
Write the slope-intercept form of the equation for the line given the slope and y-intercept (equation: y=mx+b) Slope = 5, y-inte
Rufina [12.5K]

Answer:

y=5x+2

Step-by-step explanation:

Slope formula:

y=mx+b

- m stands for slope

- b stands for y intercept.

Plug the information in:

y=5x+2

3 0
3 years ago
1. A soccer field has an area (A = LW) that is represented by the polynomial 1 point
matrenka [14]

Answer:

(x + 6)(x - 6)

Step-by-step explanation:

Given

See attachment for soccer field

Required

The possible dimension of the field

From the attachment, we have:

Area = x^2 - 36

Length = x +a

Width = x + b

So, we have:

Length * Width = Area

This gives:

(x + a)(x + b) = x^2 - 36

Express 36 as 6^2

(x + a)(x + b) = x^2 - 6^2

Express as difference of two squares

(x + a)(x + b) = (x + 6)(x - 6)

Hence, the dimension is: (x + 6)(x - 6)

6 0
3 years ago
Consider a polynomial p(x) with a degree of 9. What is the largest possible number of x-intercepts and the largest possible numb
tia_tia [17]

Answer:

The largest possible number of x intercept is 9 while the largest possible number of relative max/min is 8

Step-by-step explanation:

For any polynomial of degree n with distinct and real solutions, it can have at most n different x intercepts. This would imply it can have at most 9 distinct real solutions.

It can also have at most n-1 relative max/min in alternating order. This is best illustrated when such polynomial is sketched on a graph.

For example a quadratic expression is a polynomial of degree 2 and has at most 2 distinct solutions and 1 relative max/min.

In this question, for the polynomial, its degree (n) = 9

So it can have at most 9 x intercepts and at most 8 relative max/min.

3 0
3 years ago
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