All categories

3 years ago

Use the given scale factor and the side lengths of the scale drawing to

Mathematics

1 answer:

gavmur [86]3 years ago

5 0

Answer:

Step-by-step explanation:

A scale drawing is a reduced or enlarged form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced or enlarged at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

a = 12 inches / 6 = 2 inches

b = 9 inches / 6 = 1.5 inches

You might be interested in

A 747 airplane is 762 inches tall how tall is it in feet

Bumek [7]

Divide by 12 BC it really be like that sometimes

5 0

3 years ago

What is 11.1 divided by <br> 9.25

expeople1 [14]

Answer:

1.2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can someone explain triangle sum theorem?

Debora [2.8K]

The angle sum property of a triangle is the sum of the interior angles of the given triangle.
The total sum of the interior angels of a triangle =180

5 0

3 years ago

Read 2 more answers

A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What

vladimir2022 [97]

Answer:

The perimeter of the triangle is $12\ units$

Step-by-step explanation:

Let

$A(-3,1),B(1,1),C(1,-2)$

we know that

The perimeter of triangle is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-3,1),B(1,1)$

substitute in the formula

$AB=\sqrt{(1-1)^{2}+(1+3)^{2}}$

$AB=\sqrt{(0)^{2}+(4)^{2}}$

$AB=4\ units$

step 2

Find the distance BC

$B(1,1),C(1,-2)$

substitute in the formula

$BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}$

$BC=\sqrt{(-3)^{2}+(0)^{2}}$

$BC=3\ units$

step 3

Find the distance AC

$A(-3,1),C(1,-2)$

substitute in the formula

$AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}$

$AC=\sqrt{(-3)^{2}+(4)^{2}}$

$AC=5\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=4+3+5=12\ units$

6 0

3 years ago

For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?

Nastasia [14]

Answer:

$k=0$ and $k=3$ .

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of $k$ that makes those coordinates equal.

$k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0\\$

Using the null factor property, we have

$k=0\\k-3=0 \implies k=3$

Therefore, the given relation is not a function when $k=0$ and $k=3$ .

7 0

3 years ago