Answer:
Step-by-step explanation:
Given a circle centred at the point P(-4,-6) and passing through the point
R(2,2).
To find its equation, we follow these steps.
Step 1: Determine its radius, r using the distance formula
For point P(-4,-6) and R(2,2)
Step 2: Determine the equation
The general form of the equation of a circle passing through point (h,k) with a radius of r is given as:
Centre,(h,k)=P(-4,-6)
r=10
Therefore, the equation of the circle is:
Answer:
x=2 true solution
x=-3 extraneous
Step-by-step explanation:
sqrt(x+7) -1 = x
Add 1 to each side
sqrt(x+7) -1+1 = x+1
sqrt(x+7) = x+1
Square each side
(sqrt(x+7))^2 = (x+1)^2
x+7 = x^2 +2x+1
Subtract x from each side
7 = x^2 +x +1
Subtract 7 from each side
0 = x^2 +x - 6
Factor
0 = (x+3)(x-2)
Using the zero product property
x+3 = 0 x-2 =0
x=-3 x=2
Check solutions
x=-3
sqrt(-3+7) -1 = -3
sqrt(4) -1 = -3
3 =-3 extraneous
x=2
sqrt(2+7) -1 = 2
sqrt(9) -1 = 2
3 -1 =2
2 =2 true
Answer:
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Step-by-step explanation: