Answer:
1/5
Step-by-step explanation:
Divide both numerator and denominator by 6:
1/5
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
If a=c and b=c then a=c this is transitive property
Answer:
okay thanks didn't expect this lol
"Assuming a fair coin<span> and a fair 6-sided </span>die<span>. </span>Coin<span> has 2 sides with </span>equal probability<span>, 50% each. </span>Die<span> has 6 sides with </span>equal probability<span>, 1/6 odds </span>for<span> each side. ... The</span>probability of getting heads<span> is 1/2, and the </span>probability of getting<span> 5 or 6 is 1/3, and so you simply multiply 1/2 x 1/3, which is 1/6."</span>
