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Nadusha1986 [10]
3 years ago
13

Why did the cow hate the farmer

Mathematics
2 answers:
STALIN [3.7K]3 years ago
4 0

Answer:

The farmer ate the cow

Step-by-step explanation:

postnew [5]3 years ago
4 0
Idk give me my points
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This is the back side of the paper
vodomira [7]

Answer:

The answers are given below.

Step-by-step explanation:

8) A) acute               9) C) acute                  10) D) right                 11) B) acute  

12) A) straight          13) A) acute               14) D) right                     15) C) ∠L

16) B) ∠HIG               17) B) ∠DEC              18) B) ∠K                         19) C) ∠G

20) C) ∠KLJ

We know that ,

1. when 0° < θ < 90°, θ is acute.

2. when  θ = 90°  θ  is right

3. when 90° < θ < 180°, θ is obtuse

4. when  θ = 180°  θ  is straight

6 0
3 years ago
Graph the rational function y=x/x^2+2x+1. Both branches of the rational function pass through which quadrant?
Hitman42 [59]

Answer:

Quadrant 3

Step-by-step explanation:

Here we have to graph the function y = x/(x^2 + 2x + 1)

The denominator can be factored.

x^2 + 2x + 1 = (x + 1)(x + 1)

y = x/(x + 1)(x + 1)

Now we have to graph this function and see in which quadrant the function's both branches passes through.

Herewith I have attached the graph.

Here we can see both branches pass through Quadrant 3.

I hope this will helpful.

Thank you.


4 0
3 years ago
Read 2 more answers
At a large midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen
nasty-shy [4]

Answer:

B. Z=1.98

Step-by-step explanation:

1) Data given and notation  

X_{1}=20 represent the number of sampled freshmen finished in the bottom third of their high school class in 1993

X_{2}=10 represent the number of sampled freshmen finished in the bottom third of their high school class in 1997

n_{1}=100 sample 1 selected

n_{2}=100 sample 2 selected

p_{1}=\frac{20}{100}=0.20 represent the proportion of sampled freshmen finished in the bottom third of their high school class in 1993

p_{2}=\frac{10}{100}=0.0023 represent the proportion ofsampled freshmen finished in the bottom third of their high school class in 1997

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion graduated in the bottom third of their high school class is higher for 1993 than 1997 , the system of hypothesis would be:  

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{20+10}{100+100}=0.15

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.20-0.10}{\sqrt{0.15(1-0.15)(\frac{1}{100}+\frac{1}{100})}}=1.98  

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =P(Z>1.98)=0.024  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion graduated in the bottom third of their high school classes in 1993 is not significant higher than the proportion in 1997.  

3 0
4 years ago
Can someone help me please
Tomtit [17]
It would affect the mean the most
6 0
3 years ago
I've given up on math, help would be wildly appreciated
REY [17]

Answer:

1. \frac{2}{3} probability

2. head represents cats (let's say) and tails represent dogs, flip two coins to determine whether the family has 2 cats or 2 dogs or 1 cat and 1 dog.

3. Take two coins, flip them, record heads and tails of each flip for 50 flips (I ain't no doing this)

4 - 6. answer these questions based on the data you got...

The End

3 0
3 years ago
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