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Sonja [21]
3 years ago
12

Richard and his friend Julie collect coins as a hobby. Richard has 8 more coins than Julie. If they have 28 altogether how many

coins did Julie have?
Mathematics
1 answer:
Anna [14]3 years ago
6 0

Answer:

Julie had 10 coins

Step-by-step explanation:

Since there are 28 coins and Richard has 8 more coins than Julie

You can subtract 8 from 28 and get 20

then you would divide 20 by 2 since there are two people( Richard and Julie)  Which would give you 10

Since Richard has 8 more coins and each of them have ten you would add 8 to the 10 and you would get 18

Meaning that Richard had 18 coins and Julie had 10 coins

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28 4/7 simplify chang percent to a fractiom
Tresset [83]
4/7 to a percent is about 57 percent.
6 0
3 years ago
Read 2 more answers
25 POINTS PLEASE HELP ME!! Sam conjectures that for x ≤ - 2, it is true that x^5 + 7 > x^3. Is Sam’s conjecture correct? Why
CaHeK987 [17]

The true statement about Sam’s conjecture is that the conjecture is not correct

<h3>How to determine if Sam’s conjecture is correct or not?</h3>

Sam’s conjecture is given as:

For x ≤ - 2

It is true that x^5 + 7 > x^3.

The inequality x ≤ - 2 means that the highest value of x is -2

Assume the value of x is -2, then we have:

(-2)^5 + 7 > (-2)^3

Evaluate the exponents

-32 + 7 > -8

Evaluate the sum

-25 > -8

The above inequality is false because -8 is greater than -25 i.e. -8 > -25 or -25 < -8

Hence, the true statement about Sam’s conjecture is that the conjecture is not correct

Read more about conjectures at

brainly.com/question/20409479

#SPJ1

5 0
2 years ago
————PLEASE HELP————-
GuDViN [60]

Answer:

The diameter of Circle P is the same length as the radius of Circle Q.

Step-by-step explanation:

The radius of Circle Q is half of 52cm. So you would divide 52 by 2 and get 26cm as the radius of Circle Q. Therefore, the length of the diameter of Circle P is the same length as the radius of Circle Q.

4 0
3 years ago
Find all solutions of the equation: 2cos^2x-cosx=1
Art [367]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

——————————

Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

     \mathsf{2t^2-t-1=0}


Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

     \mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}


Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

3 0
3 years ago
A refrigerator costs $580 a year to run. A family purchases a new one for $1200 that will save them 22% annually in energy costs
NeTakaya

Answer:

It will take nine years and four months for the refrigerator to pay for itself.

Step-by-step explanation:

The new refrigerator which costs $1200, saves the family 22% annually in energy cost.

Since the old refrigerator costs $580 to run, we want to determine how many years it will take for 22% of $580 per year to make $1200.

22% of $580

= 580 × 0.22

= 127.6

That is, it saved then $127.6 per year.

Now,

$1200/127.6

≈ 9.4

Which means, it will take 9 years and 4 months for the refrigerator to pay for itself.

7 0
3 years ago
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