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3 years ago

WILL MARK BRAINLIEST

Mathematics

1 answer:

tankabanditka [31]3 years ago

7 0

So the toll for bicycles is $0.50
2•4•0.5

Possible scenario:
1) There were 4 bicycles cross the bridge in the AM and 4 in the PM that day.
2) 4 groups of 2 bicyclists crossed the bridge that day.
...

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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

Solve for x to the nearest 10th.<br> 410 = 1080(0.915)^x

Hunter-Best [27]

Answer:

410/1080=(0.915)^x

0.379=(0.915)^x

ln0. 379/ln0.915=x

X=10.903

4 0

3 years ago

(2x^3+10x^2)/(x^2+x-20) divided by (2x^2)/(x-4)

Nutka1998 [239]

Answer:

Step-by-step explanation:

Who knew the answer would be 1 LOL

hope this helps :)

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3 years ago

Which phrase best describes the correlation between the variables?

Mandarinka [93]

The best answer would be B, moderate negative.
Visually, you can tell looking at the scatter plot and going from left to right, the value of y generally gradually decreases. The reason it isn't a strong negative is because there are still some values that stray away from this pattern.

3 0

3 years ago

Which expression is equivalent to sec^2xcot^2x?

Lady_Fox [76]

$\sec x=\dfrac{1}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}$

$\sec^2x\cot^2x=\dfrac{1}{\cos^2x}\cdot\dfrac{\cos^2x}{\sin^2x}=\dfrac{\cos^2x}{\cos^2x\sin^2x}=\dfrac{1}{\sin^2x}$

8 0

3 years ago

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