Find the slope of the line between 10, -1 and -8, 6 A. 2/5 B.-18/7 C.5/2 D.-7/18
2 answers:
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Answer:
Segment EH and segment E prime H prime both pass through the center of dilation (A)
The complete question related to this found on brainly (ID:16812154) is stated below:
Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the dilation?
E(0,5) F(1,1) G(-2,1) H(0,1)
a) segment EH and segment E prime H prime both pass through the center of dilation.
b)The slope of segment EF is the same as the slope of segment E prime H prime.
c) segment E prime G prime will overlap segment EG. segment
d) EH ≅ segment E prime H prime.
Step-by-step explanation:
∆EFG = Original image
∆EFG is dilated to give ∆E'F'G'
∆E'F'G' = New image
Scale factor = 3
Center of dilation = (0,1) = H(0,1)
Coordinates ∆EFG : E(0,5) F(1,1) G(-2,1)
To determine the statement that is true about the dilation from the options,
First we would make a diagram on the coordinates of ∆EFG and center of dilation (H).
Find attached the diagram.
Length GF = 3unit
Length G'F' = 3×scale factor = 9unit
Length EH = 4unit
Length E'H' = 4×scale factor = 12unit
Then we would move 3units to the left on same line from G to get the coordinate of G'(mark the point).
Also move 3units to the right on same line from F to get the coordinate of F'(mark the point).
Both of these give length of G'F' = 9unit
Now move 8units to the top from E to get the coordinate of E'(mark the point).
From this you get length E'H' = 12unit
Draw lines connecting the three points to get ∆E'F'G'
See diagram for better understanding
From the diagram, EH and E'H' both pass through (0,1). The other options are wrong.
Therefore, Segment EH and segment E prime H prime both pass through the center of dilation (A)
Answer:
Jason is incorrect.
The caterpillar's rate is 2 ft/min
Step-by-step explanation:
The rate of motion is defined as the quotient between the distance covered (in our case 16 feet) divided by the time it took to cover that distance (in our case 8 minutes)
Then, the rate is: