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Bess [88]
4 years ago
12

graph each equation identify the conic section. any lines of symmetry, and the domain and range. x^2+y^2=4

Mathematics
1 answer:
Natasha_Volkova [10]4 years ago
4 0

Answerdjhehhshdhhdhshhsbdbhdbrhdhsh:

Step-by-step explanation:

Shhdndbhdhrhh

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Reduce a<br> to lowest terms.<br> [?]72/81
elena55 [62]

Answer:

8/9

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6 0
3 years ago
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Identify the surface with the given vector equation. r(u, v) = 2 sin(u) i + 5 cos(u) j + v k, 0 ≤ v ≤ 5 plane hyperbolic parabol
olchik [2.2K]
Note that this just produces three parametric equations:

x(u) = 2 \sin(u)
y(u) = 5 \cos(u)
z(v) = v

In the x-y plane, this is just he parametric equation for an ellipse (as a function of u). The z is simply a linear function. 

The surface is then an ellipse extruded along the z-axis. We get a elliptic cylinder.
6 0
3 years ago
The graph below shows the solution set of which inequality? 
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I hope this helps you

6 0
3 years ago
When a particular mass-spring system is started by stretching the spring 3 cm, one complete oscillation takes 4 seconds.
11Alexandr11 [23.1K]

Answer:

A. 5.16 s.

B. 5.66 s.

Step-by-step explanation:

A.

For a simple harmonic motion,

T = 2pi (sqrt * (l/g))

Given:

L1 = 3 cm

T1 = 4 s

L2 = 5 cm

T2 = ?

4 = 2pi*sqrt(3/g)

g = 7.4

At, L2,

T2 = 2pi*sqrt(5/7.4)

= 5.16 s.

B.

M1 = M1

M2 = 2*M1

For a simple harmonic motion,

T = 2pi (sqrt * (m/k))

4 = 2pi (sqrt * (M1/k))

M1/k = 0.405

Inputting the above values,

T2 = 2pi (sqrt * (2*M1/k))

= 2pi (sqrt * (2 * 0.405))

= 5.66 s.

4 0
3 years ago
Please solve using the image. No links.
Nesterboy [21]

Answer:

1/10 + 1/2 = 1/10 + <em><u>5/10</u></em> = <em><u>6/10</u></em>

6 0
3 years ago
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