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umka21 [38]
3 years ago
9

How can they been proven congruent ?

Mathematics
1 answer:
telo118 [61]3 years ago
7 0
The two angles marked are congruent.
That is one pair of congruent angles.   ------->    A
Then the vertical angles are congruent.
That is a second pair of congruent angles.    -------> A
Finally, we have the two sides marked congruent.
That is one pair of congruent sides.    ------> S

Put together what we have above, and it gives us AAS.
You might be interested in
Find the perimeter of triangle ABC with vertices A(6, 3), B(6, - 2) , and C(- 4, 3) .
anyanavicka [17]

Answer:

26.2 units

Step-by-step explanation:

We are given the points/vertices

A(6, 3),

B(6, - 2) , and

C(- 4, 3)

Step two

Let us find the distances between the given points/vertices

A-B =A(6, 3) to B(6,-2)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6-6)²+(-2-3)²)

d=√(-2-3)²)

d=√(-5)²)

d=5 units

B-C=B(6, - 2) to C(-4, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((-4-6)²+(3+2)²)

d=√(-10)²+(5)²)

d=√100+25

d=√125

d=11.2 units

C-A=C(-4, 3) to A(6, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6+4)²+(3-3)²)

d=√(10)²

d=√100

d=10 units

Hence the perimeter is 5+11.2+10

P=26.2 units

4 0
3 years ago
The slope of the line is 0. It passes through the point (-3,4). Identify two other points on the line. Justify you answer
BARSIC [14]

Answer:

Two other points: (2, 4) (6, 4)

Step-by-step explanation:

A line with a slope = 0 is a horizontal line [with a y-intercept of (0, <em>b</em>)], given by the linear equation, <em>y</em> = 4<em>.  </em>This means that the y-coordinate will always equal to 4, regardless of its corresponding x-coordinate. Basically, we could choose any x-coordinate to pair with the y-coordinate of 4.

I chose the ordered pairs, (2, 4) and (6, 4).

Attached is a screenshot of the graphed linear equation, y = 4.        

5 0
2 years ago
Find the value of x.
Sholpan [36]

Answer:

x = √21.

Step-by-step explanation:

Triangles ADB and BCD are similar.

So their corresponding sides are in the same ratio:

x / 7 = 3 / x

x^2 = 21

x = √21.

3 0
3 years ago
What is the quadratic in vertex form that has a vertex of (-1, 5)<br><br> Options in image
dimaraw [331]

Answer:

Third option

y = (x+1) ^ 2 + 5

Step-by-step explanation:

In this case we must write a quadratic equation in the vertex form.

We have the vertice. (-1, 5)

We know that the vertex form for a quadratic equation is:

y = (x-h) ^ 2 + k.

Where (h, k) is the vertex.

So if the vertex is (-1, 5), the equation sought is:

y = (x-(-1)) ^ 2 + 5

y = (x+1)) ^ 2 + 5

Therefore the answer is the Third option.

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!!!!!!!!!!!
TEA [102]

Answer: I would say D.

Its a guess ok, i have no idea.

5 0
2 years ago
Read 2 more answers
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