The product of two even numbers is even.
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Things to think about:
Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?
Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?
Why did I specifically say that m and k were integers?
The product of two odd numbers is an odd number.
Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.
The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as
2 ( 2mk + m + k ) + 1 which is an odd number.
Answer:
No
Step-by-step explanation:
The two shown sides would have to be and equal solved number.
They are not.
Orange is the correct answer.
Ok, I'm not giving you the answer. Instead, I'm going to give you the way to solve it. Then, you can do it yourself, message it to me, and I will check it.
Do .11 x 25. Remember to add the decimal back in.
Answer:
2x+a=5bx
Step 1: Add -2x to both sides.
a+2x+−2x=5bx+−2x
a=5bx−2x
Answer:
a=5bx−2x
Step-by-step explanation:
