Answer:
The factors of given expression are 10+10√2 and 10-10√2.
Step-by-step explanation:
We have given a quadratic expression.
s²-20s-100
We have to find factors of given expression.
We use quadratic formula to find factors.
x = (-b±√b²-4ac) / 2a
From given expression, a = 1 , b = -20 and c = -100
Putting values in above formula, we have
x = (-(-20)±√(-20)²-4(1)(-100) ) / 2(1)
x = (20±√400+400 ) / 2
x = (20±√800) / 2
x = (20± √400×2) / 2
x = (20±20√2) / 2
x = 10±10√2
Hence, the factors of given expression are 10+10√2 and 10-10√2.
The limit is x---->4-
The negative show that x approaches from the left
Now
As x approaches 4 from the left ... Means This number should be less than 4 (<4) but really close to 4.
Let's pick a Number
Say 3.99
Substitute this... You have
3.99/3.99-4
3.99/-0.01
If we choose x to be 3.999
we will have
3.999/-0.001
Notice the pattern... As x approaches 4 from the left... This limit will approach NEGATIVE INFINITY
Why?
As you approach 4 from the left... 3.9,3.99,3.999... You notice that the denominator becomes negative and EXTREMELY SMALL... and when you divide by an extremely small Number..... You'll get a relatively HUGE VALUE(You can try this... Use a calc... Divide any number of choice by a very small number... say.. 0.0000001.... You'll get a huge result
In our case... The denominator is negative... So it Will Approach a very Huge Negative Number
Hence
Answer.. X WILL APPROACH NEGATIVE INFINITY.
Vertical asymptotes are the zeroes of the denominator of a function
The denom. is x-4
Equate to zero to get the asymptote
x-4=0
x=4
Hence... There will be a vertical asymptote at x=4.
Have a great day!
Answer:
x = 3.255 cm
Step-by-step explanation:
Given:
⇒ y = 10cm
⇒ θ = 19
To find:
⇒ Value of "n"
Solution
⇒ By Pythagoras theorem
⇒ Δ Sin θ = n/y
⇒ sin 19° = n/10
⇒ 0.3255 = n/10
⇒ n = 0.3255 × 10
⇒ n = 3.255 cm
Hence, the answer is = n = 3.255 cm.
Answer: 0.04 meters
Step-by-step explanation:
Convert cm to meters by dividing the length by 100.
4/100= = 0.04
The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.
Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is
π (radius) (height) = π (1/y)² ∆y = π/y² ∆y
and the volume of a stack of n such disks is
where 
is a point sampled from the interval [1, 5].
As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,
