Try comparing your solution with the following:
Solution:
Answer:
Check:
![2[10-13(\frac{40}{17})]+9(\frac{40}{17})=-34(\frac{40}{17})+60\\-20=-20](https://tex.z-dn.net/?f=2%5B10-13%28%5Cfrac%7B40%7D%7B17%7D%29%5D%2B9%28%5Cfrac%7B40%7D%7B17%7D%29%3D-34%28%5Cfrac%7B40%7D%7B17%7D%29%2B60%5C%5C-20%3D-20)
<em>Hope this was helpful.</em>
If you will simplify this expression you will get this (9x + 3)(6y + 5)
and the factor, which is <span>b)6y+5. </span>
It would be 82 2/3 since 1/3 minis 2/3 would equal -1/3 you subtract that from 83 and get 82 2/3
He used 11/12 of sugar.
(1) I multiplied the factors and denominators by eachothers denominators
(2) I ended up with the two converted fractions: 8/12 and 3/12. The reason for this step is because if the two fractions have the smae denominator, it helps make it easier to add the fraction.
(3) I added the fractions, getting the sum of 11/12
Good question!
<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span><span>=<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span></span><span>=<span><span><span>2<span>(<span>x+4</span>)</span></span><span>(<span><span><span>x^2</span>−<span>4x</span></span>+19</span>)
</span></span><span>x+4</span></span></span><span>=<span><span><span>2<span>x^2</span></span>−<span>8x</span></span>+<span>38= is the answer</span></span></span>
