The error is clearly choice B.
11.2y - 7.4y should be subtracted not added.
Answer: Choice B
A force of 182.6 lb should be applied to lift 700 lb object.
<h3>How to calculate the force?</h3>
Let the force required to lift be F
Total length = 29 in.
Distance of short end from pivot = in.
Distance from long end = 29-6 = 23 in.
Now Equating moments
F × 23 = 700x6
23F = 4200
F = 4200/23
= 182.6 lb
A force of 182.6 lb should be applied to lift 700 lb object.
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I divide 40 into 4 even groups
9514 1404 393
Answer:
- 63 mph
- 3 donut holes per kid
- $0.70 per pound
- $2.25 per km
Step-by-step explanation:
In this context, "per" and "for" mean "divided by."
- 630 mi/(10 h) = 63 mi/h
- (24 dh)/(8 kid) = 3 dh/kid
- $3.50/(5 lb) = $0.70 /lb
- $32/(14 2/9 km) = $32/(128/9 km) = $(9/4)/km = $2.25 /km
