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Nata [24]
3 years ago
13

Create and solve a linear equation that represents the model, where circles and a square are shown evenly balanced on a balance

beam.
A. + 7 = 12; x = 5
B. x = 5 + 7; x = 12
C. x + 5 = 7; x = 2
D. x + 7 = 5; x = -2

Mathematics
1 answer:
Murljashka [212]3 years ago
5 0

Answer:

C

Step-by-step explanation:

We can notice that the balance beam has in one side 7 balls and in the other one 5 balls and a square

The balance beam is balenced

Let x be the square mass

  • x+5 = 7            substract five from each side
  • x+5-5 = 7-5
  • x = 2

The solution is 2

C fits perfectly what we prooved

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Please help me!!!!!!
Stels [109]

Answer: 72.5

Step-by-step explanation:

The average of 2 points is the midpoint so if I add 70 and 75 to get 145 and divide by the number of numbers which is 2 I get 72.5

7 0
2 years ago
HELP MEE PLEASEEEE BROO !!!
Anika [276]

Answer:

5

Step-by-step explanation:

Scale factor is just the amount every side is multiplied by.

7*5=35

6 0
3 years ago
Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the
nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}

Where :

m = mass of the oebjct in motion

m_o = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = 3\times 0^8 m/s

We have :

1) Mass of the Dave = m_o=66 kg

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = m_o=66 kg

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}

v=2.973\times 10^8 m/s

Dave should be moving at speed of 2.973\times 10^8 m/s.

4 0
3 years ago
The sum of three consecutive even numbers is one hundred sixty-two. What is the smallest of the three numbers?
zepelin [54]
Since the numbers are consecutive, they must be near each other in size, and therefore near one-third of 168. And since the lower number is -2 off the middle, and the upper number is +2 from the middle, the middle number must be exactly one-third of 168—otherwise the sum of the three could never be 168. Labelling the three consecutive numbers as x, y, and z:

x + y + z = 168

(y-2) + y + (y+2) = 168.

3y = 168

y = 56

therefore the smallest number (x) = 54.
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1




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