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3 years ago

HELP PLEASE

Mathematics

2 answers:

Viktor [21]3 years ago

8 0

Answer:

your answer is option B. x≤-2

LuckyWell [14K]3 years ago

6 0

3x < -6

x < -2

B is your correct answer

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Given the the table of values below which of the following ordered pairs are found on the graph of the inverse function?

Alja [10]

Answer:

Step-by-step explanation:

From the table we see that

$f(-2)=12\\ \\f(-1)=10\\ \\f(0)=8\\ \\f(1)=6\\ \\f(2)=4$

Thus, the inverse function has the rule

$f^{-1}(12)=-2\\ \\f^{-1}(10)=-1\\ \\f^{-1}(8)=0\\ \\f^{-1}(6)=1\\ \\f^{-1}(4)=2$

This gives us that ordered pairs

$(12,-2),\ (10,-1),\ (8,0),\ (6,1),\ (4,2)$

are on the graph of the inverse function

4 0

3 years ago

Read 2 more answers

If measure of angle 1=30, then measure of arc ab=

Mnenie [13.5K]

An arc of a circle has the same measure as the central angle that intercepts it.

Central angle 1 intercepts arc AB.

The measure of central angle 1 is the same as the measure of angle AB.

The measure of arc AB is 30 deg.

5 0

3 years ago

Ryan has 9 lollipops and 5 chocolate bars. What is the ratio of lollipops to chocolate bars?

anzhelika [568]

Answer:

9:5

ratios are just putting the numbers next to each other with ':' in the middle

Step-by-step explanation:

4 0

3 years ago

In 4 minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt

kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 minutes, a conveyor belt moves 800 pounds of recyclable

aluminum from the delivery truck to a storage area. A smaller belt

moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are used, find how long it takes to move the cans

to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = $\frac{1}{4}$ shifting/min

Rate of Smaller Belt = $\frac{1}{6}$ shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = $\frac{1}{x}$ shifting/min

Now,

$\frac{1}{4}$ + $\frac{1}{6}$ = $\frac{1}{x}$

⇒ $\frac{6 + 4}{24} = \frac{1}{x}$

⇒ $\frac{10}{24} = \frac{1}{x}$

⇒10x = 24

⇒x = $\frac{24}{10}$ = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

andrew11 [14]

Ummm not to freak you out but what’s that in the background?

3 0

3 years ago