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nika2105 [10]
3 years ago
5

Hello please help i’ll give brainliest

Mathematics
2 answers:
madreJ [45]3 years ago
7 0

Answer:

A

Step-by-step explanation:

zhuklara [117]3 years ago
5 0
The answer is the first one
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Someone please explain this to me.
stich3 [128]

Answer:

A is the answer

Step-by-step explanation:

Becuase if it has the same radius and the same height. then they will both be equal.

8 0
3 years ago
Say whether each of these numbers is a fraction, a decimal, or a whole number: ⅗, 18.2, 47!
denpristay [2]

Answer:

Fraction, decimal, whole number

Step-by-step explanation:

if it has a line, it's a fraction. If it has a dot, it's a decimal. If it has none of the above, it's a whole number

6 0
3 years ago
Which of the following is a solution to the equation 4x2+4x−3=0?
Readme [11.4K]

Answer:

-1.5

Step-by-step explanation:

4x² + 4x - 3 = 0

(2x + 3)(2x - 1) = 0

2x + 3 = 0  or  2x - 1 = 0

x = -3/2   or x = 1/2

Answer: -1.5

6 0
3 years ago
Read 2 more answers
Based on a study of population projections for 2000 to​ 2050, the projected population of a group of people​ (in millions) can b
Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

A(t) = 11.19(1.009)^t

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, t=0 and in 2014, t=14. Mathematically,

\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}

A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm y=a^x (where a is a constant) is \dfrac{dy}{dx}=a^x\ln a. Let's use in this in finding the derivative of A(t).

A\prime(t) = \dfrac{A}{t}=11.19\cdot1.009^t\ln1.009

In the year 2014, t=14.

A\prime(14) =11.19\cdot1.009^14\ln1.009=0.114

6 0
3 years ago
7
Marat540 [252]

Answer:

Plan A equation:   y = 10x + 30

Plan B equation:  y = x + 80

Plan C equation: y = 5x + 50

Plan A costs the same as Plan C in 4 months

Plan A is the better option if you use 0 - 4 GBs of data each month

Plan B becomes the better deal when 8 months pass

Step-by-step explanation:

<u>When does Plan A cost the same as Plan C?</u>

Set the equations equal to each other (the cost) and solve for x (time in months)

10x + 30 = 5x + 50

5x = 20

x = 4 months

<u>Which plan is best if you only use 0-4 GBs of data a month?</u>

Test the maximum and minimum values to check which plan costs less

At 0 GBs of data used per month

Plan A:  y = 0 + $ 30 = $30 total

Plan B: y = 0 +$80 = $80 total

Plan C: y = 0 + $50 = $50 total

At 4 GBs of data used per month

Plan A: y = $ 40 + $ 30 = $ 70

Plan B: y = $ 4 + $ 80 = $ 84

Plan C: y = $ 20 + $ 50 = $ 70

Comparing the plans at maximum and minimum amount of GBs used, only one plan has the lowest cost overall. Even though Plan C is the same price at 4 GBs as Plan A, when you use 0 GBs you will end up paying more in Plan C than Plan A. Therefore, Plan A is the better option

<u>When does Plan B become the best deal?</u>

When you plot the different Plans on a graph, the slope intercept of x = 7.5 (rounded up to 8) yields the lowest cost for plan B

5 0
3 years ago
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