the answer is 0.6 you gotta divide and multiply
Answer:
900 calories
Step-by-step explanation:
First you have to find the unit rate, how many calories are there in ONE cracker? To find that you have to divide 60 ÷ 12 = 5 and to check with the other one, 75 ÷ 15 = 5
So, one cracker is 5 calories. Now, how many calories are in 180 crackers? You multiply, 180 x 5 = 900
That means there are 900 calories in 180 crackers.
Hope that helps and have a great day!
The correct answer is:
[B]: "
22 " .
_________________________________________________________Explanation:_________________________________________________________Given:_________________________________________________________
;
Solve when: "n = 3" ;
Rewrite the expression; substituting "3" for all values of "n" ; as follows:
→

;
The "6" cancels out to "2" ; & the "3" cancels out to "1" ;
→ {since: " {6 ÷ 3 = 2}" ; and since: " {2 ÷ 2 = 1}" .
_________________________________________________________→ Since the "denominator" is "1" ; and any value, divided by "1"; results in that original value; we can eliminate the denominator.
→ Now, we can rewrite the expression as:
_________________________________________________________ → " 2(3² + 2)" ;
= 2(9 + 2) ;
= 2(11) ;
= "
22 " .
_________________________________________________________ → The answer is: "
22 " ; which is:
Answer choice: [B]: "
22 " .
_________________________________________________________
Answer: A
Step-by-step explanation:
A linear function is described as:
https://tex.z-dn.net/?f=f(x)%20%3D%20ax%20%2B%20b
When the value of x = 0, then you're left with
https://tex.z-dn.net/?f=f(x)%20%3D%20b
In this question, the speed of sound is the linear function while the temperature is the independent variable. When T = 0, you're left with
https://tex.z-dn.net/?f=S(0)%20%3D%20331.4
Which means the speed of sound in air when temperature is 0°C is 331.4m/s.
Answer:
70/3
Step-by-step explanation:
- Multiply: 23*3
- 23*3=69
- Add: 69+1
- 69+1=70
- 70/3
<em>Hope this helped!! :)</em>
<em>Brainliest?!?!</em>
<em>Stay safe and have a wonderful day/afternoon/night!!!</em>