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xxTIMURxx [149]

3 years ago

7

Fr33 p0ints/ umm? please help me with this question

2 answers:

UkoKoshka [18]3 years ago

7 0

A because negative means moves to the right when it comes to x axis and when it comes to y axis you move down the amount of spaces. if positive on x axis move right and positive on y axis move up

VARVARA [1.3K]3 years ago

4 0

Last choice Bc -1.5 is x value so go right and -1 is y value that goes down Bc it’s negative

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mr_godi [17]

Answer:

$V = \frac{2L\sqrt{3}}{3} \pi}$

$A = 4\pi + \sqrt{3L^{2} + 16}$

Step-by-step explanation:

Figure of cone is missing. See attachment

Given

Radius, R = 2m

Let L = KL=LM=KM

Required:

Volume, V and Surface Area, A

<u><em>Calculating Volume</em></u>

Volume is calculated using the following formula

$V = \frac{1}{3} \pi R^{2} H$

Where R is the radius of the cone and H is the height

First, we need to determine the height of the cone

The height is represented by length OL

It is given that KL=LM=KM in triangle KLM

This means that this triangle is an equilateral triangle

where OM = OK = $\frac{1}{2} KL$

OK = $\frac{1}{2}L$

Applying pythagoras theorem in triangle LOM,

|LM|² = |OL|² + |OM|²

By substitution

L² = H² + ( $\frac{1}{2}L$ )²

H² = L² - $\frac{1}{4}L$ ²

H² = L² (1 - $\frac{1}{4}$ )

H² = L² $\frac{3}{4}$

H² = $\frac{3L^{2} }{4}$

Take square root of bot sides

$H = \sqrt{\frac{3L^{2} }{4}}$

$H = \frac{L\sqrt{3}}{2}$

Recall that $V = \frac{1}{3} \pi R^{2} H$

$V = \frac{1}{3} \pi 2^{2} * \frac{L\sqrt{3}}{2}$

$V = \frac{1}{3} \pi * 4} * \frac{L\sqrt{3}}{2}$

$V = \frac{1}{3} \pi} * {2L\sqrt{3}}$

$V = \frac{2L\sqrt{3}}{3} \pi}$

in terms of $\pi$ an d L where L = KL = LM = KM

<u><em>Calculating Surface Area</em></u>

Surface Area is calculated using the following formula

$H = \frac{L\sqrt{3}}{4}$

$A=\pi r(r+\sqrt{h^{2} +r^{2} } )$

$A=\pi * 2(2+\sqrt{((\frac{L\sqrt{3}}{2})^{2} +2^{2} } )$ )

$A=\pi * 2(2+\sqrt{{\frac{3L^{2}}{4} } + 4 }$ )

$A=\pi * 2(2+\sqrt{{\frac{3L^{2}+16}{4} } })$

$A=2\pi(2+\sqrt{{\frac{3L^{2}+16}{4} } })$

$A = 2\pi (2 + \frac{\sqrt{3L^{2} + 16}}{\sqrt{4}} )$

$A = 2\pi (2 + \frac{\sqrt{3L^{2} + 16}}{2} )$

$A = 2\pi (2 + {\frac{1}{2} \sqrt{3L^{2} + 16})$

$A = 4\pi + \sqrt{3L^{2} + 16}$

6 0

2 years ago

FREE PO!NTS!!!! (50)<br> This is for big900 and someone else<br><br> IM taking attendance say "HERE"

Sergio039 [100]

Answer:

here

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Consider the procedure used below to solve the given equation.

slavikrds [6]

Answer is D you can plug it in to check it as well

5 0

2 years ago

32 is what percent of 160?

jonny [76]

32/160 = 0.20

so 32 is 20% of 160

7 0

3 years ago

Which expressions are equivalent to 10/10^3/4?

drek231 [11]

$\frac{10}{10 {}^{ \frac{3}{4} } } = 10 {}^{1 - \frac{3}{4} } = 10 { }^{ \frac{4 - 3}{4} }$

$10 {}^{ \frac{ 1}{4} }$

6 0

2 years ago