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photoshop1234 [79]
3 years ago
15

A square painting is surrounded by a frame. The outside edges of the frame are x inches in length and there is a 4-inch border b

etween the painting and the frame. What is the total area of the border?
Mathematics
2 answers:
Rashid [163]3 years ago
4 0

Answer:

16x-64 square inches

Step-by-step explanation:

Given that a square painting is surrounded by a frame. The outside edges of the frame are x inches in length and there is a 4-inch border between the painting and the frame.

Thus the square frame consists of an outer square with side x inches and inner square with side x-4(2)

The area of the border

=

area of outer square-area of inner square

=x^2-(x-8)^2

= (2x-8)(8)

=16x-64

Nadusha1986 [10]3 years ago
3 0
The total area of the frame is therefore 2(4x) + 2(4)(x-8) = 8x + 8x - 64 = 16x - 64
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Which of the following fractions is closest to the decimal 0.35
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What is the common ratio for the geometric sequence? 18,12,8,163,… Enter your answer in the box.
uysha [10]

Answer:

\frac{2}{3}.

Step-by-step explanation:  

We have been given a geometric sequence 18,12,8,16/3,.. We are asked to find the common ratio of given geometric sequence.

We can find common ratio of geometric sequence by dividing any number by its previous number in the sequence.

\text{Common ratio of geometric sequence}=\frac{a_2}{a_1}

Let us use two consecutive numbers of our sequence in above formula.

a_2 will be 12 and a_1 will be 18 for our given sequence.

\text{Common ratio of geometric sequence}=\frac{12}{18}

Dividing our numerator and denominator by 6 we will get,

\text{Common ratio of geometric sequence}=\frac{2}{3}

Let us use numbers 8 and 16/3 in above formula.

\text{Common ratio of geometric sequence}=\frac{\frac{16}{3}}{8}

\text{Common ratio of geometric sequence}=\frac{16}{3*8}

\text{Common ratio of geometric sequence}=\frac{2}{3}

Therefore, we get \frac{2}{3} as common ratio of our given geometric sequence.




6 0
3 years ago
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