Given: 9x > -36.

The volume of a cylinder is 156 x cm3. What is the volume of a cone with the same base and height as the cylinder?

Flura [38]

Answer: SECOND OPTION (52 cm³)

Step-by-step explanation:

The formula for calculate the volume of a cone is:

$V{co}=\frac{1}{3}r^{2}h\pi$

Where r is the radius and h is the height.

The formula for calculate the volume of a cylinder is:

$V{cy}=r^{2}h\pi$

Where r is the radius and h is the height.

As you can see, the difference between the the formulas is that r²hπ of the cone is divided by 3. Therefore, if you know the volume of the cylinder and you know that the cone has the same base and height as the cylinder, you have to divide the volume of the cylinder by 3 to obtain the volume of the cone.

Therefore, the result is:

$V{co}=\frac{156cm^3}{3}=52cm^3$

7 0

3 years ago

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Printing a newsletter cost $1.50 per copy plus $450 in printers fee. The copies are sold for $3 each. How many copies of the new

e-lub [12.9K]

1.50x + 450 = 3x
450 = 3x - 1.50x
450 = 1.50x
450/1.50 = x
300 = x

300 copies must be sold to break even

6 0

3 years ago

Read 2 more answers

YALL PLSSSSSSSS HELP IM SHAKING I NEED HELP PLSS

Vilka [71]

Answer:

someone is adding dont worrie

Step-by-step explanation:

8 0

2 years ago

How can you use order numbers that are written as fractions, decimals, and percents?

galina1969 [7]

2.5 4/5 8% that is an example of written fractions decimal and percents

7 0

3 years ago

Daily high temperatures in St. Louis for the last week were as follows: 95, 92, 93, 92, 95, 90, 90 (yesterday). a) The

hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as follows:

95, 92, 93, 92, 95, 90, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the 2-day moving average

Solution:

a)

- The set of 3 day moving average is as follows:

4. (95 + 92 + 93) ÷ 3 = 93.33⁰C

5. (92 + 93 + 92) ÷ 3 = 92.33⁰C

6. (93 + 92 + 95) ÷ 3 = 93.33⁰C

7. (92 + 95 + 90) ÷ 3 = 92.33⁰C

8. (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3. (95 + 92) ÷ 2 = 93.5⁰C

4. (95 + 93) ÷ 2 = 92.5⁰C

5. (93 + 92) ÷ 2 = 92.5⁰C

6. (92 + 95) ÷ 2 = 93.5⁰C

7. (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

Error Error^2

3. 93.5⁰C 0.5 0.25

4. 92.5⁰C 0.5 0.25

5. 92.5⁰C 2.5 6.25

6. 93.5⁰C 3.5 12.25

7. 92.5⁰C 2.5 6.25

8. 90⁰C

- The mean absolute deviation as follows:

MAD = Sum of all errors / 5

MAD = (0.5+0.5+2.5+3.5+2.5) / 5

MAD = 1.9

d)

- The mean squared error deviation as follows:

MSE = Sum of all error^2 / 5

MSE = (0.25+0.25+6.25+12.25+6.25) / 5

MSE = 5.05

4 0

3 years ago